In the reaction sequence CH_2=CH_2 xrightarro | vedclass

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Question

(A) The reaction sequence is as follows:$1$. $CH_2=CH_2$ reacts with $HOCl$ (hypochlorous acid) to form ethylene chlorohydrin $(X)$: $CH_2=CH_2 + HOCl

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$ClCH_2-CH_2OH$ and $NaHCO_3$

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(A) The reaction sequence is as follows:$1$. $CH_2=CH_2$ reacts with $HOCl$ (hypochlorous acid) to form ethylene chlorohydrin $(X)$: $CH_2=CH_2 + HOCl \rightarrow CH_2(OH)-CH_2(Cl)$.$2$. $CH_2(OH)-CH_2(Cl)$ (ethylene chlorohydrin) reacts with a base like $NaHCO_3$ or $NaOH$ to undergo hydrolysis or epoxide formation followed by ring opening to yield ethylene glycol $(CH_2(OH)-CH_2(OH))$.$3$. Thus,$X$ is $CH_2(OH)-CH_2(Cl)$ and $Y$ is $NaHCO_3$.

In the reaction sequence $CH_2=CH_2$ $\xrightarrow{HOCl} X$ $\xrightarrow{Y} CH_2(OH)-CH_2(OH)$,$X$ and $Y$ respectively are:

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